Question 32.WE.1: The attenuation (absorption) coefficient of bone is 600 m^−1...

The attenuation (absorption) coefficient of bone is 600  m^{−1} for X-rays of energy 20 keV. A beam of such X-rays has an intensity of 20  Wm^{−2}. Calculate the intensity of the beam after passing through a 4.0 mm thickness of bone

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Step 1 Write down the quantities that you are given; make sure that the units are consistent.
I_{0} = 20  Wm^{−2}
x = 4.0 mm = 0.004 m
µ = 600  m^{−1}
Step 2 Substitute in the equation for intensity and solve.
Hint: Calculate the exponent (the value of –µx) first.
I = I_{0}  e^{−µx}

= 20 × e^{−(600  ×  0.04)} = 20 × e^{−2.4}

= 1.8  Wm^{−2}
So the intensity of the X-ray beam will have been reduced to about 10% of its initial value after passing through just 4.0mm of bone.

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