Question 23.1: Given V1 = 10 V, R1 = 100 Ω, R2 = 100 Ω, and R3 = 100 Ω, the...
Given V_1 = 10 V, R_1 = 100 Ω, R_2 = 100 \ Ω, and R_3 = 100 Ω, the RTD will vary from 100 Ω at 0°C to 138.5 Ω at 100°C. Ignore the resistance of the cabling. Using Fig. 23-5, solve for V_{AB} at 20°C, where the RTD = 107.79 Ω, and at 100°C, where the RTD = 138.5 Ω.

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Temperature = 20°C | Temperature = 100°C |
V_{AB} = V_A − V_B | V_{AB} = V_A − V_B |
V_{AB}=V_1\left(\frac{RTD}{R_1+RTD}\right) -V_1\left(\frac{R_3}{R_2+R_3} \right) | V_{AB}=V_1\left(\frac{RTD}{R_1+RTD}\right) -V_1\left(\frac{R_3}{R_2+R_3} \right) |
R_2 = R_3 ∴ | R_2 = R_3 ∴ |
V_{AB}=V_1\left(\frac{RTD}{R_1+RTD}\right) -V_1\left(\frac{1}{2} \right) | V_{AB}=V_1\left(\frac{RTD}{R_1+RTD}\right) -V_1\left(\frac{1}{2} \right) |
V_{AB}=10 \ V\left(\frac{107.79 \ Ω}{100 \ Ω + 107.79 \ Ω} \right)-10 \ V \left(\frac{1}{2} \right) | V_{AB}=10 \ V\left(\frac{138.5 \ Ω}{100 \ Ω + 138.5 \ Ω} \right)-10 \ V \left(\frac{1}{2} \right) |
V_{AB} = 187.45 mV | V_{AB} = 807.13 mV |
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