Question 10.25: Find the rate of shear deformation in the flow described by u...

Find the rate of shear deformation in the flow described by u = kx²y + α/y, v = −kxy² + β/x, w = ε, where k, α, β, and ε are constants.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The shear deformation rate is given by Eq. 10.41 as

D=\left[\begin{matrix} \frac{\partial u}{\partial x}- \frac{1}{3}\left(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z}\right)&\frac{1}{2}\left(\frac{\partial u}{\partial y}+\frac{\partial v}{\partial x}  \right)&\frac{1}{2}\left(\frac{\partial u}{\partial z}+\frac{\partial w}{\partial x}  \right) \\\frac{1}{2}\left(\frac{\partial v}{\partial x}+\frac{\partial u}{\partial y}  \right)& \frac{\partial v}{\partial x} -\frac{1}{3}\left(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z}\right)&\frac{1}{2}\left(\frac{\partial v}{\partial z}+\frac{\partial w}{\partial y}  \right) \\\frac{1}{2}\left(\frac{\partial w}{\partial x}+\frac{\partial u}{\partial z}  \right)&\frac{1}{2}\left(\frac{\partial w}{\partial y}+\frac{\partial v}{\partial z}  \right) &\frac{\partial w}{\partial z} -\frac{1}{3}\left(\frac{\partial u}{\partial x}+\frac{\partial v}{\partial y}+\frac{\partial w}{\partial z}\right) \end{matrix} \right]Because of the many derivatives involved, it is best to solve this problem with a symbolic mathematics code or calculator. The result is

D=\left[\begin{matrix} 2kxy&\frac{1}{2}\left[\left(\frac{kx^2y^2 −α }{y^2} \right)-\left(\frac{kx^2y^2+\beta }{x^2} \right)\right]&0\\\frac{1}{2}\left[\left(\frac{kx^2y^2 −α }{y^2} \right)-\left(\frac{kx^2y^2+\beta }{x^2} \right)\right]&-2kxy&0\\0&0&0 \end{matrix} \right]

We see that in this flow the shear deformation varies significantly with position. This is normally the case for all but the simplest flow fields.

Related Answered Questions

Question: 10.23

Verified Answer:

This exercise can be solved by using Eqs. 10.73: u...