Question 15.8: Determine the critical depth and flow velocity in a 10 m wide...
Determine the critical depth and flow velocity in a 10 m wide rectangular channel carrying 50 m³/s.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Learn more on how we answer questions.
No sketch is necessary here. We know the flowrate and channel width; thus we can use Eq. 15.41a to calculate the critical depth as
y_C=\left[\frac{Q^2}{gw^2} \right]^{1/3}=\left[\frac{(50\ m^3/s)^2 }{(9.81\ m/s^2)(10\ m)^2} \right]=1.37\ m
The critical velocity is found from Eq. 15.41c as
V_C=\sqrt{gy_C}=\sqrt{(9.81\ m/s^2)(1.37\ m)}=3.67\ m/s
Related Answered Questions
Question: 15.19
Verified Answer:
Figure 15.50 can serve as a sketch. To find the vol...
Question: 15.18
Verified Answer:
We can calculate the flowrate of a full-width recta...
Question: 15.11
Verified Answer:
From SB = tan θ = (h1 − h2)/L, which is Eq. 15.34,...
Question: 15.10
Verified Answer:
We first calculate the upstream Froude number for ...
Question: 15.9
Verified Answer:
The geometry of the flow channel is shown in Figure...
Question: 15.17
Verified Answer:
Applying Eq. 15.58e, Q =[2gw^2y^2 _1y^2 _2/...
Question: 15.16
Verified Answer:
No sketch is necessary here. From Table 15.1 the M...
Question: 15.15
Verified Answer:
We know that the volume flowrate is given by Eq. 15...
Question: 15.14
Verified Answer:
We can think of this channel first as a whole and s...
Question: 15.13
Verified Answer:
The culvert is sketched in Figure 15.38. From Tabl...