Question 22.12: What is the load current in Fig. 22-21? What is the output r...
What is the load current in Fig. 22-21? What is the output ripple?

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The LM7812 produces a regulated output voltage of +12 V. Therefore, the load current is:
I_{L}=\frac{12 \ V}{100 \ \Omega }=120 \ mA
We can calculate the peak-to-peak input ripple with the equation given in Chap. 4:
V_{R}=\frac{I_L}{fC}=\frac{120 \ mA}{(120 \ Hz)(1000 \ μF) }=1 \ V
Summary Table 22-1 shows a typical ripple rejection of 72 dB for the LM7812. If we convert 72 dB mentally (60 dB + 12 dB), we get approximately 4000. With a scientific calculator, the exact ripple rejection is:
Summary Table 22-1 Typical Parameters of Popular IC Voltage Regulators at 25°C |
||||||||
Number | V_{out}, V | I_{max}, A | Load Reg, mV | Line Reg, mV | Rip Rej, dB | Dropout, V | R_{out}, mΩ | I_{SL}, A |
LM7805 | 5 | 1.5 | 10 | 3 | 80 | 2 | 8 | 2.1 |
LM7806 | 6 | 1.5 | 12 | 5 | 75 | 2 | 9 | 0.55 |
LM7808 | 8 | 1.5 | 12 | 6 | 72 | 2 | 16 | 0.45 |
LM7812 | 12 | 1.5 | 12 | 4 | 72 | 2 | 18 | 1.5 |
LM7815 | 15 | 1.5 | 12 | 4 | 70 | 2 | 19 | 1.2 |
LM7818 | 18 | 1.5 | 12 | 15 | 69 | 2 | 22 | 0.2 |
LM7824 | 24 | 1.5 | 12 | 18 | 66 | 2 | 28 | 0.15 |
LM78L05 | 5 | 100 mA | 20 | 18 | 80 | 1.7 | 190 | 0.14 |
LM78L12 | 12 | 101 mA | 30 | 30 | 80 | 1.7 | 190 | 0.14 |
LM2931 | 3 to 24 | 102 mA | 14 | 4 | 80 | 0.3 | 200 | 0.14 |
LM7905 | −5 | 1.5 | 10 | 3 | 80 | 2 | 8 | 2.1 |
LM7912 | −12 | 1.5 | 12 | 4 | 72 | 2 | 18 | 1.5 |
LM7915 | −15 | 1.5 | 12 | 4 | 70 | 2 | 19 | 1.2 |
LM317 | 1.2 to 37 | 1.5 | 0.30% | 0.02%/V | 80 | 2 | 10 | 2.2 |
LM337 | −1.2 to −37 | 1.5 | 0.30% | 0.01%/V | 77 | 2 | 10 | 2.2 |
LM338 | 1.2 to 32 | 5 | 0.30% | 0.02%/V | 75 | 2.7 | 5 | 8 |
RR=antilog\frac{72 \ dB}{20}=3981
The peak-to-peak output ripple is approximately:
V_R=\frac{1 \ V}{4000}= 0.25 \ mV
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