Question 11.7: A nonconservative holonomic system having two degrees of fre...
A nonconservative holonomic system having two degrees of freedom with generalized coordinates \left(q_1, q_2\right) and corresponding generalized forces Q_1^N=-m b^2 v \dot{q}_1, Q_2^N=0, has a Lagrangian function
L=\frac{1}{2} m a^2 \sin ^2 q_1 + m b^2\left(\dot{q}_2 + \frac{a}{b} \cos q_1\right)^2 + \frac{1}{2} m b^2\left(\dot{q}_1 + c\right)^2, (11.48a)
in which a, b, c, and m are constants. Derive the Lagrange equations.
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Notice that q_2 is ignorable and Q_2^N=0. Therefore, we have immediately by (11.47) the corresponding momentum integral
p_e\left(\dot{q}_r, q_r, t\right)=\frac{\partial L\left(\dot{q}_r, q_r, t\right)}{\partial \dot{q}_e}=\gamma_e, \text { a constant. } (11.47)
p_2=\frac{\partial L}{\partial \dot{q}_2}=2 m b^2\left(\dot{q}_2 + \frac{a}{b} \cos q_1\right)=\gamma_2, \text { a constant. } (11.48b)
Caution:We must continue to apply the Lagrange equations to (11.48a) in which all of the variables are considered independent. Equation (11.48b) is a partial solution of one of these equations that necessarily relates these variables; but it is not to be substituted into the Lagrangian, it is to be used in connection with the companion equation for q_1. The second of Lagrange’s equations (11.38) yields
m b^2 \ddot{q}_1 + 2 m a b\left(\dot{q}_2 + \frac{a}{b} \cos q_1\right) \sin q_1 – m a^2 \sin q_1 \cos q_1=Q_1^N=-m b^2 v \dot{q}_1 . (11.48c)
We now use (11.48b) to eliminate \dot{q}_2 from (11.48c) to obtain
\ddot{q}_1 + v \dot{q}_1 + \frac{a}{b} \sin q_1\left(\frac{\gamma_2}{m b^2} – \frac{a}{b} \cos q_1\right)=0 (11.48d)
The two equations (11.48b) and (11.48d), in principle, determine q_1(t) and q_2(t).