Question 5.57: A 150 μF capacitor is charged to a potential of 150 V. The c...

A 150 μF capacitor is charged to a potential of 150 V. The capacitor is then removed from the charging source and connected to a 2 MΩ resistor. Determine the capacitor voltage 1 minute later.

The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

We will solve this problem using the tabular method rather than using the exponential formula.

First we need to find the time constant:

C × R = 150 μF × 2 MΩ = 300 s

Next we find the ratio of t to CR. After 1 minute, t = 60 s, therefore the ratio of t to CR is:

\frac{t}{C R}=\frac{60}{300}=0.2

Referring to the table above,we find that when t/CR = 0.2, the ratio of instantaneous value to final value (k) for decay is 0.8187. Thus:

t/CR k (ratio of instantaneous value to final value)
Exponential
growth
Exponential decay
0.0 0.0000 1.0000
0.1 0.0951 0.9048
0.2 0.1812 0.8187 (see Example 5.57)
0.3 0.2591 0.7408
0.4 0.3296 0.6703
0.5 0.3935 0.6065
0.6 0.4511 0.5488
0.7 0.5034 0.4965
0.8 0.5506 0.4493
0.9 0.5934 0.4065
1.0 0.6321 0.3679
1.5 0.7769 0.2231
2.0 0.8647 0.1353
2.5 0.9179 0.0821
3.0 0.9502 0.0498
3.5 0.9698 0.0302
4.0 0.9817 0.0183
4.5 0.9889 0.0111
5.0 0.9933 0.0067

\frac{v_C }{V_{ S }}=0.8187

or

{v_C} = 0.8187 × 150 = 122.8 V

Related Answered Questions

Question: 5.67

Verified Answer:

W = 0.5 LI²      and hence: \begin{aligned}...
Question: 5.51

Verified Answer:

The value (0.22) is stated in μF and the tolerance...
Question: 5.43

Verified Answer:

The charge stored will be given by: \begin{...
Question: 5.34

Verified Answer:

•    First digit:            orange = 3 •    Secon...
Question: 5.33

Verified Answer:

•    First digit:            blue = 6 •    Second ...
Question: 5.32

Verified Answer:

•    First digit:            brown = 1 •    Second...
Question: 5.27

Verified Answer:

To find the resistance at 125°C we use: R_t...