Question 15.9: Finding the Percent Ionization of a Weak Acid Find the perce...

Finding the Percent Ionization of a Weak Acid

Find the percent ionization of a 2.5 M HNO_{2} solution.

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To find the percent ionization, you must find the equilibrium concentration of H_{3}O^{+}. Follow the  procedure in Example15.5, shown in condensed form here. HNO_{2}(aq) + H_{2}O(l) \xrightleftharpoons[]{}H_{3}O^{+}(aq) + NO_{2}^{-}(aq)

[HNO_{2}] [H_{3}O^{+}] [NO_{2}^{-}]
Initial 2.5 ≈0.00 0.0
Change -x +x +x
Equil 2.5-x x x
K_{a} = \frac{[H_{3}O^{+}][NO_{2}^{-}]}{[HNO_{2}]} = \frac{x^{2}}{2.5 – \cancel{x}} (x is small)
4.6× 10^{-4} =\frac{ x^{2}}{2.5}
x = 0.034
Therefore, [ H_{3}O{+} ] = 0.034 M.
Use the definition of percent ionization to calculate it. (Since the percent ionization is less than 5%, the x is small approxi-mation is valid.) % ionization = \frac{[H_{3}O^{+}]_{equil}}{[HA]_{init}}× 100%
= \frac{0.034 \cancel{M}}{2.5 \cancel{M}}× 100%
= 1.4%

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