Question 10.7.1: PD Control of a Neutrally Stable Second-Order Plant PD contr...

PD Control of a Neutrally Stable Second-Order Plant

PD control of a neutrally stable second-order plant is shown in Figure 10.7.1. Investigate its performance for step and ramp inputs for c ≥ 0.

10.7.1
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

The output equation is
\Theta(s) = \frac{K_{P}  +  K_{D} s}{I s^{2}  +  (c  +  K_{D})s  +  K_{P}} \Theta_{r}(s)  −  \frac{1}{I s^{2}  +  (c  +  K_{D})s  +  K_{P}} T_{d} (s)
The characteristic polynomial is I s^{2} + (c + K_{D})s + K_{P} , and the system is stable if c + K_{D} > 0 and if K_{P} > 0. For unit-step inputs, the steady-state command response is K_{P} /K_{P} = 1, which
is perfect, and the disturbance response is −1/K_{P} . The damping ratio is
ζ = \frac{c  +  K_{D}}{2 \sqrt{I K_{P}}}
If ζ ≤ 1, the time constant is given by
\tau = \frac{2I}{c  +  K_{D}}
For P control (with K_{D} = 0), ζ = c/2 \sqrt{I K_{P}} . Thus, introducing rate action allows the proportional gain K_{P} to be selected large to reduce the steady-state  disturbance response, while K_{D} can be used to achieve an acceptable damping ratio. The rate action also helps to stabilize the system by adding damping (if c = 0, the system with P control is not stable).

Related Answered Questions