Question 1.10: Given three resistors, where R1 = 1 Ω, R2 = 27 Ω, and R3 = 5...

Using Equation (1.43) from above,

1/R_{parallel-equiv}=1/R_{1}+1/R_{2}+1/R_{3}+….+1/R_{n}.      (1.43)

1/R_{parallel-equiv}=1/R_{1}+1/R_{2}+1/R_{3}.

1/R_{equiv}=1/1+1/27+1/500=1/0.9624 .

R_{equiv} = 0.9624   Ω     

Note that the parallel equivalent resistor of 0.9624 Ω is smaller than the smallest given resistor, which is 1 Ω.