Using data from Appendix [latex]2[/latex], calculate [latex]∆H^\circ_\text{rxn}[/latex] for [latex]\text{Ag}^+(aq) + \text{Cl}^– (aq) → \text{AgCl}(s)[/latex]. Strategy Use Equation 10.18 [latex][∆H^\circ_\text{rxn} = ∑n∆H^\circ_\text{f} (\text{products}) – ∑m∆H^\circ_\text{f} (\text{reactants})][/latex] and [latex]∆H^\circ_\text{f}[/latex] values from Appendix [latex]2[/latex] to calculate [latex]∆H^\circ_\text{rxn}[/latex]. Setup The ([latex]∆H^\circ_\text{f}[/latex]) values for [latex]\text{Ag}^+(aq), \text{Cl}^–(aq)[/latex], and [latex]\text{AgCl}(s)[/latex] are [latex]+105.9, –167.2[/latex], and [latex]–27.0 \text{kJ/mol}[/latex], respectively.

Using Equation 10.18 [latex]∆H^\circ_\text{rxn} = ∆H^\circ_\text{f} (\text{AgCl}) - [∆H^\circ_\text{f} (\text{Ag}^+) + ∆H^\circ_\text{f}(\text{Cl}^–)] [/latex] [latex]= –127.0 \text{kJ/mol} – [(+105.9 \text{kJ/mol}) + (–167.2 \text{kJ/mol)}][/latex] [latex]= –127.0 \text{kJ/mol} – (–61.3 \text{kJ/mol}) = –65.7 \text{kJ/mol}[/latex]

Question 10.8: Using data from Appendix 2, calculate ∆H°rxn for Ag^+(aq) + ...

Chemistry: Atoms First

Using data from Appendix $2$ , calculate $∆H^\circ_\text{rxn}$ for $\text{Ag}^+(aq) + \text{Cl}^– (aq) → \text{AgCl}(s)$ .

Strategy Use Equation 10.18 $[∆H^\circ_\text{rxn} = ∑n∆H^\circ_\text{f} (\text{products}) – ∑m∆H^\circ_\text{f} (\text{reactants})]$ and $∆H^\circ_\text{f}$ values from Appendix $2$ to calculate $∆H^\circ_\text{rxn}$ .

Setup The ( $∆H^\circ_\text{f}$ ) values for $\text{Ag}^+(aq), \text{Cl}^–(aq)$ , and $\text{AgCl}(s)$ are $+105.9, -167.2$ , and $–27.0 \text{kJ/mol}$ , respectively.

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