Question 1.8: Two pieces of material are interlocked as shown in Figure 1....
Two pieces of material are interlocked as shown in Figure 1.25. If the ultimate stress in shear for the material is 38 MPa. What force is required to fracture the pieces in shear?

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We observe that the machine component is in single shear and clearly, the shear area, A_{ S } is
A_{ S }=30 \times 80=2400 mm ^2
Therefore, for equilibrium in the horizontal direction,
P=\tau \times A_S=38 \times 2400=91200 N =91.2 kN
therefore, force required to fracture is P = 912.2 kN.
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