Question 9.9: A potassium iodide solution may be used in a diet that is lo...

A potassium iodide solution may be used in a diet that is low in iodine. A KI solution is prepared by dissolving 5.0 g of KI in enough water to give a final volume of 250 mL. What is the mass/volume percent (m/v) of KI in the solution?

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STEP 1   State the given and needed quantities.

ANALYZE THE PROBLEM Given Need Connect
5.0 g of KI solute, 250 mL of KI solution mass/volume percent (m/v) \frac{mass  of  solute }{volume  of  solution} \times 100%

STEP 2   Write the concentration expression.

Mass/volume percent (m/v) = \frac{mass  of  solute }{volume  of  solution} \times 100 %

STEP 3   Substitute solute and solution quantities into the expression and calculate.

Mass/volume percent (m/v) = \overset{Two  SFs}{\underset{Two  SFs}{\frac{5.0  g  KI}{250  mL  solution}}} \times 100 % = 2.0% \underset{Two  SFs}{(m/v)  KI  solution }

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