Question 3.9.3: Computing Elasticity of Demand and Changes in Revenue Suppos...
Computing Elasticity of Demand and Changes in Revenue
Suppose that
f (p) = 400(20 − p)
is the demand for an item at price p (in dollars) with p < 20. (a) Find the elasticity of demand. (b) Find the range of prices for which E < −1. Compare this to the range of prices for which revenue is a decreasing function of p.
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The elasticity of demand is given by
E=\frac{p}{f(p)} f^{\prime}(p)=\frac{p}{400(20-p)}(-400)=\frac{p}{p-20}.
We show a graph of E=\frac{p}{p-20} in Figure 3.98. Observe that E < −1 if
\frac{p}{p-20}<-1or p>-(p-20) \text {. } \quad \text { Since } p-20<0 \text {. }
Solving this gives us 2 p>20
or p>10 \text {. }
To analyze revenue, we compute R=p f(p)=p(8000-400 p)=8000 p-400 p^2. Revenue decreases if R^{\prime}(p)<0 . \text { From } R^{\prime}(p)=8000-800 p, we see that R^{\prime}(p)=0 if p=10 \text { and } R^{\prime}(p)<0 \text { if } p>10. Of course, this says that the revenue decreases if the price exceeds 10.
