Question 4.7.5: Using the Trapezoidal Rule Compute the Trapezoidal Rule ap...

Using the Trapezoidal Rule

Compute the Trapezoidal Rule approximations with n = 4 (by hand) and n = 8, 16, 32, 64 and 128 (using a program) for \int_0^1 3 x^2 d x.

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As we saw in examples 7.1 and 7.2, the exact value of this integral is 1. For the Trapezoidal Rule with n = 4, we have

T_4(f)=\frac{1-0}{(2)(4)}\left[f(0)+2 f\left(\frac{1}{4}\right)+2 f\left(\frac{1}{2}\right)+2 f\left(\frac{3}{4}\right)+f(1)\right]

= \frac{1}{8}\left(0+\frac{3}{8}+\frac{12}{8}+\frac{27}{8}+3\right)=\frac{66}{64}=1.03125.

Using a program, you can easily get the values in the accompanying table.

 

n T_n(f) Error
4 1.03125 0.03125
8 1.0078125 0.0078125
16 1.00195313 0.00195313
32 1.00048828 0.00048828
64 1.00012207 0.00012207
128 1.00003052 0.00003052

 

We have included a column showing the error (the absolute value of the difference between the exact value of 1 and the approximate value). Notice that (as with the Midpoint Rule) as the number of steps doubles, the error is reduced by approximately a factor of 4.

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