Question 10.1: Load-Line Analysis If the circuit of Figure 10.5 has VSS = 2...

First, we locate the ends of the load line. Substituting v_D = 0 and the values given for V_SS and R into Equation 10.5 yields i_D = 2 mA. These values plot as point B in Figure 10.7. Substitution of i_D = 0 and circuit values results in v_D = 2 V. These values plot as point A in the figure. Constructing the load line results in an operating point of V_DQ ≅ 0.7 V and I_DQ ≅ 1.3 mA, as shown in the figure.

V_{SS}=R_{iD}+v_{D}           (10.5)