Question 10.2: Load-Line Analysis Repeat Example 10.1 if VSS = 10 V and R =...
Load-Line Analysis
Repeat Example 10.1 if VSS = 10 V and R = 10 kΩ.
If we let vD = 0 and substitute values into Equation 10.5, we find that iD = 1 mA. This is plotted as point C in Figure 10.7.
If we proceed as before by assuming that iD = 0, we find that vD = 10 V. This is a perfectly valid point on the load line, but it plots at a point far off the page. Of course, we can use any other point satisfying Equation 10.5 to locate the load line. Since we already have point C on the iD axis, a good point to use would be on the right-hand edge of Figure 10.7. Thus, we assume that vD = 2 V and substitute values into Equation 10.5, resulting in iD = 0.8 mA. These values plot as point D. Then, we can draw the load line and find that the operating-point values are VDQ ≅ 0.68V and IDQ = 0.93 mA.
V_{SS}=R_{iD}+v_{D} (10.5)
