A 10 × 10 table consists of positive integers such that for every five rows and five columns, the sum of the numbers at their intersections is even. Prove that all of the integers in the table are even.
We denote the first five entries in a row as the “head” of that row. We first show that the sum of each head is even. We are given that the sum of any five heads is even; by subtracting two such sums overlapping in four heads, we deduce that the sum of any two heads is even. Now subtracting two such relations from a sum of five heads, we determine that the sum of any head is even.
By a similar argument, the sum of any five entries in a row is even.
By the same argument as above, we deduce that each entry is even.