Question 2.CA.4: A force of 500 N forms angles of 60°, 45°, and 120°, respect......

A force of 500 N forms angles of 60°, 45°, and 120°, respectively, with the x, y, and z axes. Find the components F_x, F_y, \text { and } F_z of the force and express the force in terms of unit vectors.

Question Data is a breakdown of the data given in the question above.
  • Force: 500 N
  • Angles: 60°, 45°, and 120° with the x, y, and z axes respectively.
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Step 1:
Substitute the given values for F, θx, θy, and θz into formulas (2.19). These formulas give the scalar components of F.
Step 2:
Calculate each component using the given values. Use the cosine function to find the components in each direction.
Step 3:
Plug in the calculated values of Fx, Fy, and Fz into equation (2.20). This equation gives the vector representation of F.
Step 4:
Write the final vector representation of F using the calculated values of Fx, Fy, and Fz. Use the unit vectors i, j, and k to indicate the direction of each component.
Step 5:
Explain the meaning of the plus and minus signs in the final vector representation. A plus sign indicates that the component has the same direction as the corresponding axis, while a minus sign indicates that it has the opposite direction.

Final Answer

Substitute F=500 \mathrm{~N}, \theta_x=60^{\circ}, \theta_y=45^{\circ}, \text { and } \theta_z=120^{\circ} formulas (2.19). The scalar components of F are then

F_x=F \cos \theta_x \quad F_y=F \cos \theta_y \quad F_z=F \cos \theta_z (2.19)

\begin{array}{l}F_x=(500 \mathrm{~N}) \cos 60^{\circ}=+250 \mathrm{~N} \\F_y=(500 \mathrm{~N}) \cos 45^{\circ}=+354 \mathrm{~N} \\F_z=(500 \mathrm{~N}) \cos 120^{\circ}=-250 \mathrm{~N}\end{array}

Carrying these values into Eq. (2.20), you have

\mathbf{F}=F_x \mathbf{i}+F_y \mathbf{j}+F_z \mathbf{k} (2.20)

\mathbf{F}=(250 \mathrm{~N}) \mathbf{i}+(354 \mathrm{~N}) \mathbf{j}-(250 \mathrm{~N}) \mathbf{k}

As in the case of two-dimensional problems, a plus sign indicates that the component has the same sense as the corresponding axis, and a minus sign indicates that it has the opposite sense.

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