Consider 2-methylbutane (isopentane). Sighting along the C2–C3 bond:
(a) Draw a Newman projection of the most stable conformation.
(b) Draw a Newman projection of the least stable conformation.
(c) If a CH_3 ↔ CH_3 eclipsing interaction costs 11 kJ/mol (2.5 kcal/mol) and a CH_3 ↔ CH_3 gauche interaction costs 3.8 kJ/mol (0.9 kcal/mol), make a quantitative plot of energy versus rotation about the C2–C3 bond.
CH3 ↔ CH3 eclipsing interaction costs 11 kJ/mol (2.5 kcal/mol)
CH3 ↔ CH3 gauche interaction costs 3.8 kJ/mol (0.9 kcal/mol)
(a), (b)
The energy difference between the two conformations is (1 1.0 + 6.0 + 4.0) kJ/mol – 3.8kJ/mol = 17.2kJ/mol.
(c) Consider the least stable conformation to be at zero degrees. Keeping the front of the projection unchanged, rotate the back by 60° to obtain each conformation.
\underline{at 60° }: energy = 3.8 kJ/mol \underline{at 120° }: energy = 18.0 kJ/mol \underline{at 180°} : energy = 3.8 kJ/mol
\underline{at 240°}: energy = 2 1 .0 kJ/mol \underline{at 300°} : energy = 7.6 kJ/mol
Use the lowest energy conformation as the energy minimum. The highest energy conformation is 17.2 kJ/mol higher in energy than the lowest energy conformation.