Question 2.6.20: Let BD be the bisector of angle B in triangle ABC. The circu......

Mathematical Olympiads, Problems and Solutions from Around the World, 1996-1997 [1513040]

Let BD be the bisector of angle B in triangle ABC. The circumcircle of triangle BDC meets AB at E, while the circumcircle of triangle ABD meets BC at F. Prove that AE = CF.

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