Refer to the GPA’s in Example 22 of Chapter 1, where we assume that the given GPA scores are observed values of r.v.’s X_{i},i=1,\ldots, 34 with (unknown) mean μ and (unknown) variance \sigma^{2}, both finite. Construct a confidence interval for μ with confidence coefficient approximately 95%.
In the discussion of Example 1 in Chapter 13, we saw that: \sum\limits_{i}x_{i}=100.73\operatorname{and}\sum_{i}x_{i}^{2}=304.7885, so that:
\bar{x}=\frac{100.73}{34}\simeq2.963,\quad s_{n}^{2}=\frac{304.7885}{34}-\frac{(100.73)^{2}}{34^{2}}\simeq0.187,\quad\mathrm{and}\quad s_{n}\simeq0.432.
Since z_{0.025}=1.96, formula (5) gives:
\left[{\bar{X}}_{n}-z_{\frac{\alpha}{2}}{\frac{S_{n}}{\sqrt{n}}},\quad{\bar{X}}_{n}+z_{\frac{\alpha}{2}}{\frac{S_{n}}{\sqrt{n}}}\right] (5)