Question F.4: Use the voltage-divider equation to find Vout in Figure F–4.......

Use the voltage-divider equation to find V_{\mathrm{out}} in Figure F–4. (V_{\mathrm{out}} is the voltage from the point labeled V_{\mathrm{out}} to the ground symbol.)

Figure F–4
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V_{\mathrm{out}}=12\,\mathrm{V}\times{\frac{2\,\mathrm{k}\Omega}{2\,\mathrm{k}\Omega\,+\,4\,\mathrm{k}\Omega}}

=4\,\mathrm{V}

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