0.002 moles of a substance X reacted in 18 min and 5 s. The number of photons absorbed per second is 2.0 × 10⁶. Calculate the quantum yield of the reaction (Avogadro’s number = 6.02 ×10^23).

Question

0.002 moles of a substance X reacted in 18 min and 5 s. The number of photons absorbed per second is 2.0 × 10⁶. Calculate the quantum yield of the reaction (Avogadro’s number [latex]= 6.02 ×10^{23}[/latex]).

Accepted Answer

[latex]\begin{aligned}\text{Number of molecules of X reacting} & = 0.002 \text{moles}\ &= 0.002 × 6.02 × 10^{23}\end{aligned}[/latex]

Number of photons absorbed per second = 2.0 × 10⁶

Number of photons absorbed in 18 min and 5 s = 2.0 × 10⁶ × 1085

[latex]\text{Quantum yield} =\frac{\text{ Number of molecules reacted}}{\text{Number of photons absorbed}}\[/latex]

[latex]=\frac{0.002 ×6.02 ×10^{23}}{2.0×10^6 ×1085} = 5.548×10^{11}[/latex]

Question 18.1.2: 0.002 moles of a substance X reacted in 18 min and 5 s. The ......

Related Answered Questions

Verified Answer:

1 × 10^-4 mole of a substance decomposed when it was irradiated with a light of wavelength 4800 Å. If the quantum efficiency of the reaction is 8, calculate the number of photons absorbed (Avogadro’s number = 6.02 × 10^23). ...

Verified Answer:

Calculate the energy associated with (a) one photon and (b) one einstein of radiation of wavelength 7500 Å. h = 6.62 × 10^–27 erg-s; velocity of light c = 3 ×10^10 cm s^–1 ...

Verified Answer: