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Question 7.SP.32: A 60-g bullet moving with a speed of 500 m/s strikes a 5-kg ......

A 60-g bullet moving with a speed of 500 m/s strikes a 5-kg block moving in the same direction with a speed of 30 m/s. What is the resultant speed v of the bullet and the block, assuming the bullet to be embedded in the block?

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Momentum of system before impact = momentum of system after impact

\begin{aligned}0.06(500)+5(30) & =(0.06+5) \times v \\v & =\underline{35.6 \mathrm{~m} / \mathrm{s}}\end{aligned}

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