A certain wire has a resistance R. What is the resistance of a second wire, made of the same material, that is half as long and has half the diameter?
The thickness (diameter) of the wire is denoted by D. We use R \propto L / A (Eq. 26-16) and note that A=\frac{1}{4} \pi D^2 \propto D^2 . The resistance of the second wire is given by
R=\rho \frac{L}{A}, (26-16)
R_2=R\left(\frac{A_1}{A_2}\right)\left(\frac{L_2}{L_1}\right)=R\left(\frac{D_1}{D_2}\right)^2\left(\frac{L_2}{L_1}\right)=R(2)^2\left(\frac{1}{2}\right)=2 R .