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Question 26.75: A certain x-ray tube operates at a current of 7.00 mA and a ......

A certain x-ray tube operates at a current of 7.00 mA and a potential difference of 80.0 kV. What is its power in watts?

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The power dissipated is given by the product of the current and the potential
difference: P=i\,{ V}=(7.0\times10^{-3}\ \mathrm{A})(80\times10^{3}\ \mathrm{V})=560\ \mathrm{W}.

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