Question 1.4.2: A cylinder of 1.5 m diameter and 2 m long floats in seawater......
A cylinder of 1.5 m diameter and 2 m long floats in seawater with its axis vertical. The base of the cylinder is 1.5 m below the water surface. Find the weight of the cylinder and the position of gravity if it is 0.3 m below the metacentre. Seawater weighs 10055 N/m³.
Weight of the cylinder = weight of the seawater displaced
= (π/4) × 1.5² × 1.5 × 10055 = 26653 N
Figure E 1.4.2 shows the position of the cylinder with O, G, B, M representing the centre of the base, centre of gravity, centre of buoyancy and the metacentre, respectively.
\mathrm{OB = 1.5/2 = 0.75 m and BM \frac{I}{V}=\frac{\pi d^4/64}{(\pi d^2/4)\times 1.5}= 0.09 m. }
But OM = OB + BM = 0.84 m and also = OG + MG
→ OG = 0.54 m, since MG = 3 m (given).
