A gas used in internal combustion engine had the following composition by volume : H_2 = 45\%; CH_4 = 36\%; CO = 15\%; N_2 = 4\%. Find the volume of air required for the combustion of 1 m³ of the gas.
Constituent | Amount in 1m³ of the fuel | Combustion reaction |
Volume of \bf O_2 required(m³)
|
H_2 | 0.45 m³ | H_2 +\frac{1}{2} O_2 \rightarrow H_2O | 45 ×0.5 =0.225 |
CH_4 | 0.36 m³ | CH_4 +2 O_2 \rightarrow CO_2 +2H_2O | 0.36 × 2 = 0.72 |
CO | 0.15 m³ | CO +\frac{1}{2} O_2 \rightarrow CO_2 |
0.15 × 0.5 = 0.075
|
N_2 | 0.04 m³ | ||
Total = 1.020 |