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Question 1.2.2: A given sample of petrol contains H = 15.4% and C = 84.6%. C......

A given sample of petrol contains H = 15.4% and C = 84.6%. Calculate the minimum volume of O_2 required for the combustion of this sample.

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\begin{aligned}\text{Weight of}  O_2  \text{required for combustion of 1 kg fuel} &= 3.488 ~kg\\ & = 3488 ~g.\end{aligned}

Since 1 mole = 32 g of O_2 at NTP occupies 22.4 L

\begin{aligned}\text{Therefore}  3488 ~g  \text{of}  O_2  \text{at NTP occupies} & = \frac{22.4}{32} × 3488 \\&= 2441.6 ~L\\& = 2.441 ~m^3\end{aligned}

(Since 1000 L = 1 m³)

Constituent Amount in 1 kg of petrol Combustion reaction
Weight of \bf O_2 required(kg)
H 0.154 kg H_2 +\frac{1}{2}  O_2 \rightarrow H_2O 0.154 × \frac{16}{2}= 1.232 ~kg
C 0.846 kg C + O_2 \rightarrow CO_2 0.846 × \frac{32}{12}  = 2.256 ~kg
Total  O_2 reqd = 3.488 kg

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