A ice block floating in a river is pushed through a displacement \vec{d}=(15\, m ) \hat{i}-(12\, m ) \hat{j} along a straight embankment by rushing water, which exerts a force \vec{F}=(210 \,N ) \hat{i}-(150\,N ) \hat{j} on the block. How much work does the force do on the block during the displacement?
Using Eq. 7-8 (and Eq. 3-23), we find the work done by the water on the ice block:
W=\vec{F}\cdot \vec{d} (work done by a constant force), (7-8)
\vec{a} \cdot \vec{b}=a_x b_x+a_y b_y+a_z b_z (3-23)
\begin{aligned}W &=\vec{F}\cdot \vec{d}=[(210 \,N ) \hat{i}-(150\, N ) \hat{j}] \cdot[(15 \,m ) \hat{i}-(12 \,m ) \hat{j}]=(210\, N )(15 \,m )+(-150 \,N )(-12\, m ) \\&=5.0 \times 10^3 \,J\end{aligned}.