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Question 9.2: A muffle furnace is to be designed for silicon carbide heate......

A muffle furnace is to be designed for silicon carbide heaters.

Size of heating space (nominal)     28 (W) × 22 (H) × 120 (D) cm

Maximum temperature     1400°C

Atmosphere     Air

Estimated power     15 kW

Power supply     380 V, 3 phase

Heating elements to be situated at the top across the width.

Now determine:

Number of heating elements required.
Size of elements.
Current and resistance of elements.
Transformer required.

Step-by-Step
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The width of the chamber is 28 cm. The heating element chosen must have a hot (central) zone about 28 cm.

According to Figure 9.8 the permissible surface loading (P) at 1400°C and in air atmosphere is

P = 6 W/cm²
Element temperature ~ 1,475°C
Total heating surface required

= \frac{1,5000}{6} = 2,500 cm²

For equal distribution in three phases the number of elements must be divisible by 3.
For trial consider 18 elements so that power per element will be

=\frac{15,000}{18} = 833 W/element

Hot surface for each element

=\frac{2,500}{18} = 138.89 ~ 140 cm²

Referring to Table 9.7 it can be seen that the nearest resistor has a heating length 305 mm for furnace width 279 mm.

The surface area required per element is 140 cm² . The nearest area of the heating zone is 152 cm² for a 15.8 mm diameter rod.

We have no information about the thickness of the insulation. There are four options available. They are 76, 127, 166, 191, and 229 mm. Assume a wall thickness of about 200 mm.
The nearest size is 191 mm.
The element chosen has following specifications:
Heating length      305 mm
Furnace width      279 mm
Element diameter      15.8 mm
Radiating surface      15201 mm²
Resistance      1.63 ohm
Let us try a combination of six elements in parallel. The total resistance in each phase will be

\begin{aligned}& \frac{1}{R}=\frac{6}{1.63} \\& \therefore R=\frac{1.63}{6}=0.271 \ \mathrm{ohm}\end{aligned}

Current = \sqrt{5000 / 0.271}=136 \ \mathrm{~A} / \text { phase }

Voltage = 136 × 0.271 = 36.8 V/Phase

kVA = 5 kW
Primary voltage 380/\sqrt{3} = 220 V

The transformer required is 380 V, 3 ph, 30 amp-primary; and 20, 30, 40, 50, 80 V taps on secondary with current 200 A, kVA ~ 20–25

Table 9.7 Extract from Specification Data for Silicon Carbide Heaters (Norton)

Effective heating length (mm) Width of furance chamber (mm) Diameter Nominal radiating surface (mm^2) Thickness of furance wall (mm) Overall length (mm) Nominal resistances (ohm)
9.5 9,120 76 \\ 127 \\ 165 \\ 76 483 \\ 584 \\ 600\\ 438 4.55\\ 4.62\\ 4.87\\ 3.24
11.1 10,639 127 \\ 165 \\ 191 \\ 229 \\ 76 584\\ 600\\ 711\\ 787 \\ 483 3.40\\ 3.43\\ 3.46\\ 3.50\\ 2.50
305 279 12.7 12,161 127 \\ 165 \\ 191 \\ 229 \\ 76 584\\ 600\\ 711\\ 787 \\ 508 2.54\\ 2.57 \\ 2.59\\ 2.62\\ 1.57
15.8 15,201 127 \\ 165 \\ 191 \\ 229 \\ 76 610\\ 686\\ 737\\ 813 \\ 508 1.60\\ 1.62\\ 1.63\\ 1.65\\ 1.07
19 18,239 127 \\ 165 \\ 191 \\ 229 \\ 191 610\\ 686\\ 737\\ 813\\ 787 1.08\\ 1.10\\ 1.11\\ 1.12\\ 0.063
25.4 24,323 229 \\ 343 864\\ 1,092 0.064\\ 0.066
9.8

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