A PHES system (refer to Figure 11.2) equipped with a reversible pump–turbine and motor–generator units is operating under the following conditions:
• Static head, that is, elevation difference between upper and lower reservoirs H = 600 m
• Volumetric water flow rate in pumping mode Vp = 90 m³/s
• Daily duration of pumping period τp = 8.5 h
• Overall pumping efficiency ηp = 0.83
• Volumetric water flow rate in generating mode Vt = 135 m³/s
• Daily duration of power generation period τgen= 6.5 h
• Overall power generation efficiency ηgen = 0.92
Calculate (a) the plant power output in generating mode, (b) the daily electricity generation, (c) the pumping power input, (d) the daily pumping energy demand, and (e) the turnaround efficiency of the energy storage.
1. Plant power output in generating mode
Pgen=grVtHhgen=9.81×1000×135×600×0.92=731MW2. Daily electricity generation
Egen=tgenPgen=6.5×731=4751.8MWh/day3. Pumping power input
Pp=grVρH/hp=9.81×1000×90×600/0.83=638.24MW4. Daily pumping energy demand
Ep=tpPp=8.5×638.24=5425 MWh/d5. Turnaround efficiency of PHES system based on energy output Egen and energy input Ep
ηs=Egen/Ep=4751.8/5425=0.876=87.6%.