Question 1.13: A power of 300 mW is dissipated in a circuit when a voltage ......
A power of 300 \mathrm{~mW} is dissipated in a circuit when a voltage of 1,500 \mathrm{V} is applied. Determine the current supplied to the circuit.
Step-by-Step
Current is equal to power divided by voltage. Thus:
I=P / V=300 \mathrm{~mW} / 1,500 \mathrm{V} \text { amperes }Expressing this in exponent notation gives:
I=\left(300 \times 10^{-3}\right) /\left(1.5 \times 10^{3}\right) \mathrm{A}Separating the exponents gives:
I=(300 / 1.5) \times\left(10^{-3} / 10^{3}\right) \mathrm{A} \\ I=300 / 1.5 \times 10^{-3} \times 10^{-3} \mathrm{~A}Thus, I=200 \times 10^{(-3-3)}=200 \times 10^{-6}=200 \mu \mathrm{A}
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