A radioactive sample intended for irradiation of a hospital patient is prepared at a nearby laboratory. The sample has a half-life of 83.61 h. What should its initial activity be if its activity is to be 7.4 × 10^8 Bq when it is used to irradiate the patient 24 h later?

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Using Eq. 42-16 with Eq. 42-18, we find the initial activity:

T_{1 / 2}=\frac{\ln 2}{\lambda}=\tau \ln 2         (42-18)

R=R_0 e^{-\lambda t} \quad \text { (radioactive decay), }         (42-16)

R_0=R e^{t \ln 2 / T_{1 / 2}}=\left(7.4 \times 10^8 \mathrm{~Bq}\right) e^{24 \ln 2 / 83.61}=9.0 \times 10^8  \mathrm{~Bq}.

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