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Question 3.P.17: A roller gate as shown in Fig. P. 3.17 has a span of 5 m. De......

A roller gate as shown in Fig. P. 3.17 has a span of 5 m. Determine the magnitude and direction of the resultant force on the cylinder when water just begins to overflow. Neglect weight of the gate.

P 3.17
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The horizontal force equals the force on the projected area,

γ  A  \bar{h} = 9810 × 4 × 5 × 2 = 392400  N

This acts at a distance of 1.3333 m from bottom twoards the right.

The vertical upward force is equal to the weight of the water displaced

= 5 × 9810 × π × 2^{2}/2 = 308190  N

It acts at a distance of (4r/3π) = 0.84883  m left of centre and upwards

Resultant = (392400^{2} + 308190^{2})^{0.5} = 498958  N

Taking moments about the centre,

392400 × (2 – 1.3333) – 0.84883 × 308189 = 0.

As the net moment about the centre is zero the resultant passes through the centre. The direction with horizontal is given by \tan θ = 308190 / 392400,  θ = 37.58°.

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