A sample of helium gas (He) has a volume of 6.8 L and a pressure of 2.5 atm. What is the final volume, in liters, if it has a final pressure of 1.2 atm with no change in temperature and amount of gas?
Using Boyle’s law, we can write the relationship for V_2, which we predict will increase.
\begin{aligned} & P_1=2.5\ atm \quad P_2=1.2\ atm \\ & \quad V_1=6.8\ L \quad V_2 \quad \text { Need } \\ & V_2=V_1 \times \frac{P_1}{P_2} \\ & V_2=6.8\ L \times \frac{2.5\ \cancel {atm} }{1.2\ \cancel{atm} }=14\ L \end{aligned}