Question 4.6: A sinusoidal voltage 10 V pk-pk is applied to a resistor of ......
A sinusoidal voltage 10 V pk-pk is applied to a resistor of 1 kF What value of r.m.s. current will flow in the resistor?
Step-by-Step
This problem must be solved in two stages. First we will determine the peak-peak current in the resistor and then we shall convert this value into a corresponding r.m.s. quantity.
Since I = \frac{V}{R} we can infer that I_{pk-pk} = \frac{V_{pk-pk}}{R}
From which I_{pk-pk} = \frac{10}{1,000} = 0.01 = 10 mA pk-pk
The required multiplying factor (peak-peak to r.m.s.) is 0.353. Thus:
I_{r.m.s.} = 0.353 × I_{pk-pk} = 0.353 × 10 = 3.53 mARelated Answered Questions
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