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Question 3.4: A steel plate (α = 10^−5 m²/s, k = 40 W/m/ °C), initially at......

A steel plate (α = 10^{−5} m²/s, k = 40 W/m/ °C), initially at 30 °C, is subject at x = 0 to a surface heat flux as given by Eq. (3.50), starting at time zero, with p = 1 (linear-in-time increase) and a rate of s_q = q_0/t_{ref} = 106 W/m²/s. The plate is insulated on the back side x=L= 5 cm. Calculate the temperature at 1 cm inside the flat plate at times 1, 2, and 3 seconds by using Eq. (3.47). Then, compare it with the exact values coming from the exact analytical solution defined in Section 2.3.9.

T_{M}(x)=T_{i n}+\sum\limits_{i=1}^{M}T_{i,M}(x)=T_{i n}+\sum\limits_{i=1}^{M}q_{0,i}\Delta\phi_{x,M-i}  (3.47)

q_{0}(t)=q_{0}\biggl(\frac{t}{t_{r e f}}\biggr)^{p}=s_{q}t^{p}(t\geq0) (3.50)

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The temperature at the interior point of interest x_P = 1 cm is T(x_P, t) and increases with time. If the piecewise-constant approximation of the applied surface heat flux is based on a time step Δt = 1 s, by using Eq. (3.47) the temperatures at t = l, 2, and 3 seconds are given, respectively, by

T_{1}(x_{P})=T_{i n}+q_{0,1}\phi_{1}(\tilde{x}_{P})=30.492831^{\circ}C  (3.51a)

T_{2}(x_{P})=T_{i n}+q_{0,1}\Delta\phi_{1}(\tilde{x}_{P})+q_{0,2}\phi_{1}(\tilde{x}_{P})=34.827114^{\circ}\mathrm{\large{C}} (3.51b)

T_{3}(x_{P})=T_{i n}+q_{0,1}\Delta\phi_{2}(\tilde{x}_{P})+q_{0,2}\Delta\phi_{1}(\tilde{x}_{P})+q_{0,3}\phi_{1}(\tilde{x}_{P})=47.655181^{\circ}C (3.51c)

where \phi_{M}(\tilde{x}_{P})\equiv\tilde{T}_{X22B10T0}(\tilde{x}_{P}M\Delta\tilde{t})\times L/k, with M = 1, 2 or 3. Also, \tilde{x}_{P}=x_{P}/L=0.2,\,\Delta\tilde{t}=\alpha\Delta t/L^{2}=0.004, and the first six decimal-places have been considered for the building block solution (A = 6).
The exact temperatures can be obtained from the fdX22B20T0.m MATLAB function of Section 2.3.9 as the current problem can be denoted by X22B20T1, where “2” in B20 indicates a linear-in-time increase of the surface heat-flux. They are

T(x_{P}=1\operatorname{cm},\,\Delta t=1\,{\mathrm{s}})=T_{i n}+\frac{L}{k}\underbrace{ \tilde{t}_{r e f}\tilde{T}(\tilde{x}_{P}=0.2,\;\Delta\tilde{t}=0.004,\,\tilde{t}_{r e f}=1,\,A=15)}_{=\operatorname{fd}\!\mathbf{X}22{\mathrm{B}}\!20T0(0.2, 0.004, 1,15)}

\times \underbrace{(\frac{q_0}{t_{ref}} )}_{s_{q}=10^{6}\ \mathrm{W}\ \mathrm{m}^{-2}\ \mathrm{s}^{-1}} (\frac{L^2}{\alpha } )=30.187600\ °C (3.52a)

T(x_{P}=1\operatorname{cm},\,2\Delta t=2\,{\mathrm{s}})=T_{i n}+\frac{L}{k}\underbrace{ \tilde{t}_{r e f}\tilde{T}(\tilde{x}_{P}=0.2,\;2\Delta\tilde{t}=0.008,\,\tilde{t}_{r e f}=1,\,A=15)}_{=\operatorname{fd}\!\mathbf{X}22{\mathrm{B}}\!20T0(0.2, 0.008, 1,15)}

\times\frac{q_0}{t_{ref}} (\frac{L^2}{\alpha } )=30.074329\ °C (3.52b)

T(x_{P}=1\operatorname{cm},\,3\Delta t=3\,{\mathrm{s}})=T_{i n}+\frac{L}{k}\underbrace{ \tilde{t}_{r e f}\tilde{T}(\tilde{x}_{P}=0.2,\;3\Delta\tilde{t}=0.012,\,\tilde{t}_{r e f}=1,\,A=15)}_{=\operatorname{fd}\!\mathbf{X}22{\mathrm{B}}\!20T0(0.2, 0.012, 1,15)}

\times\frac{q_0}{t_{ref}} (\frac{L^2}{\alpha } )=46.725442\ °C (3.52c)

where \tilde{t}_{r e f}\tilde{T} is independent of \tilde{t}_{r e f} (see Section 2.3.9). For this reason, the simple numerical value of \tilde{t}_{r e f} = 1 can be chosen. Also, an accuracy of one part in 10^{15} is chosen (A = 15) in such a way as the computational analytical solution can be assumed exact (see Section 2.3.5.1).
Hence, the absolute errors in the approximate temperatures are +0.305231, +0.752785, and +0.929739 °C, respectively. If these errors are normalized relatively to the maximum exact temperature rises that occur at the boundary surface x = 0 up to and including the time of interest (i.e. T(0, t) − T_{in} = 59.470803, 168.208835 and 309.019362 C, at t = l, 2, and 3 seconds, respectively), they are: 0.51, 0.45, and 0.30%, respectively. The exact temperature rises at x = 0 can still be obtained from the fdX22B20T0.m MATLAB function of Section 2.3.9.
The above errors are very small. However, if the approximate temperatures are  computed at the heated surface x = 0 of the plate by still choosing a time step of Δt = 1 s, the absolute and relative errors can be very large. In such a case, to get more accurate results, it is convenient to use smaller time steps, as shown in Table 3.4, where the temperatures ( °C) are obtained by using the fdX22B_0T0_pca.m function and the following equation that relates the dimensional and dimensionless temperatures:

T(x_{P},\,t_{M})=\,T_{i n}+\underbrace{\tilde{T}(\tilde{x}_{P},\,\tilde{t}_{M},p,A,\,M)}_{=\mathrm{fd}X22\mathrm{B}_{-}0\mathrm{T}0_{-}\mathrm{pca}} \times s_q(\frac{L}{K} )(\frac{L^2}{\alpha } )^p (3.53)

where \tilde{x}_{P}=x_{P}/L=0,\,\tilde{t}_{M}=M\Delta\tilde{t},\,\Delta\tilde{t}=\alpha\Delta t/L^{2}, p = 1, and A = 6.
Note that, when using Δt = 0.01 s, the first digits of the approximate temperatures are the same as the ones of the exact temperatures, being the underlined digits different, as shown by Table 3.4.

Table 3.4 Comparison of exact and approximate temperatures for three different time steps using the piecewise-constant approximation (fdX22B_0T0_pca.m) at x = 0.
Approximate temperature ( °C)
t, s Exact temperature ( °C) Δt =1 s M Δt = 0.1 s M Δt = 0.01 s M
1 89.470803 74.603103 1 88.921532 10 89.4{\underline{{52631}}} 100
2 198.208835 182.284519 2 197.648680 20 198.{\underline{{190553}}} 200
3 339.019362 322.617672 3 338.454385 30 339.0{\underline{{01031}}} 300

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