An air-core solenoid is wound by 40 turns of copper coil whose mean length and cross-sectional area are 5 m and 24 cm^{2}, respectively. If the permeability of free space is 4π ×10^{-7} H/m^{2}, determine the inductance.
The inductance is calculated as,
L={\frac{N^{2}\mu A}{l}}={\frac{40^{2}\times1\times4\pi\times10^{-7}\times24\times10^{-4}}{5}}=0.96\,\mathrm{{\mu H}} (5.156)