An operational amplifier has an input resistance of 2 MΩ Determine the input current when an input voltage of 5 mV is present.
Now:
R_{IN} = \frac{V_{IN}}{I_{IN}}thus
I_{IN} = \frac{V_{IN}}{R_{IN}} = \frac{5 \times 10^{-3}}{2 \times 10^{6}} = 2.5 \times 10^{-9} A = 2.5 nA