Assume an inductor with a negligible resistance is connected to a 36-V, 400-Hz line. If the circuit has a current flow of 0.2 A, what is the inductance of the inductor?
The first step is to determine the inductive reactance of the circuit:
X_{L}={\frac{{E}}{I}}
X_{L}={\frac{36\ V}{0.2\ A}}
X_{L} = 180 Ω
Now that the inductive reactance of the inductor is known, the inductance can be determined:
L = {\frac{{X}_{L}}{2\pi\mathbf{f}}}
L = \frac{180\ \Omega}{2\times\mathbb{3}.14\mathbb{16}\times400{\mathrm{~}}HZ}
L = 0.0716 H