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Question 6.2.4: Assuming the potentiometer resistance R1 is proportional to ......

Assuming the potentiometer resistance {{R}}_{1} is proportional to x, derive the expression for the output voltage {{v}}_{o} as a function of x.

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The length of the pot is L and its total resistance is {{R}}_{1} + {{R}}_{2}. Figure 6.2.5b shows the circuit diagram of the system. From the voltage-divider rule,

v_{o}={\frac{R_{1}}{R_{1}+R_{2}}}V                      (1)

Because the resistance {{R}}_{1} proportional to x,

R_{1}=(R_{1}+R_{2})\left(\frac{x}{L}\right)

Substituting this into equation (1) gives

v_{o}={\frac{x}{L}}V=K x

where K = V/L is the gain of the pot.

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