Calculate osmotic pressure for a solution containing a nonelectrolyte. The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C7H5N3O6 (227.10 g/mol), is soluble in benzene (C6H6). Calculate the osmotic pressure generated when 14.3 g of TNT is dissolved in 242 mL of a benzene solution at 298 K.

Question

Calculate osmotic pressure for a solution containing a nonelectrolyte.

The nonvolatile, nonelectrolyte TNT (trinitrotoluene), C[latex]_{7}[/latex]H[latex]_{5}[/latex]N[latex]_{3}[/latex]O[latex]_{6}[/latex] (227.10 g/mol), is soluble in benzene (C[latex]_{6}[/latex]H[latex]_{6}[/latex]). Calculate the osmotic pressure generated when 14.3 g of TNT is dissolved in 242 mL of a benzene solution at 298 K.

Accepted Answer

You are asked to calculate osmotic pressure for a solution.
You are given the mass of solute in the solution, the volume of the solution, and the temperature of the solution.
14.3 g TNT × [latex]\frac{1 ext{ mol TNT}}{227.1 ext{ g}}[/latex] = 0.0630 mol TNT

[latex]\frac{0.0630 ext{ mol TNT}}{0.242 ext{ L}}[/latex] = 0.260 M

The van’t Hoff factor (i) for the solute is 1 because it is a nonelectrolyte.
∏ = cRTi = (0.260 M)(0.082057 L · atm/K · mol)(298 K)(1) = 6.36 atm

Question 13.4.1: Calculate osmotic pressure for a solution containing a nonel......

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