Calculate the initial concentrations of each sub stance. For part (a) , calculate Q_\text{c}\text{ and compare to given }K_\text{c}.\text{ If }Q_\text{c} > K_\text{c} then the reaction proceeds to the left to make reactants from products. If Q_\text{c} < K_\text{c} then the reaction proceeds to right to make products from reactants. For part (b) , use the result of part (a) and the given equilibrium concentration of \text{PCl}_5 to find the equilibrium concentrations of \text{PCl}_3\text{ and Cl}_2.
Initial concentrations: \text{[PCl}_5] = 0.1050\text{ mol /0.5000 L} = 0.2100 \ M \\ \text{[PCl}_3] = \text{[Cl}_2 ] = 0.0450\text{ mol/0.5000 L} = 0.0900 \ M \\ \text{a) }Q_\text{c}=\frac{[\text{PCl}_3][\text{Cl}_2]}{[\text{PCl}_5]} =\frac{[0.0900][0.0900]}{[0.2100]} =0.038571=0.0386
Q_\text{c}, 0.0386,\text{ is less than }K_\text{c}, 0.042, so the reaction will proceed to the right to make more products.
b) To reach equilibrium , concentrations will increase for the products, \text{PCl}_3\text{ and Cl}_2, and decrease for the reactant , \text{PCl}_5.
\text{[PCl}_5] = 0.2065 \ M = 0.2100 – \text{x; x} = 0.0035 \ M \\ \text{[PCl}_3] = [\text{Cl}_2 ] = 0.0900 + \text{x} = 0.0900 + 0.0035 = 0.0935 \ M
Check: Calculate equilibrium constants using the calculated equilibrium concentrations: