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Question 14.12: Calculate the specific heat of a sample of glass, given that......

Calculate the specific heat of a sample of glass, given that the input of 150 joules of energy as heat to a 50.0-gram sample causes a temperature increase of 3.57°C.

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Application of Equation 14.31 yields for the specific heat

c_{sp}=\frac{c_{P}}{m}= \frac{q_{P}}{m\Delta T}               (14.31)

c_{sp}=\frac{q_{P}}{m\Delta T} =\frac{150\ J}{(50.0\ g)(3.57\ K)} =0.84\ J·g^{–1}·K^{–1}

The specific heat of glass of 0.84\ J·g^{–1}·K^{–1} is also approximately equal to the specific heat of rocks, cement, or dirt.

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