Calculating ΔE for a Reaction
The reaction of nitrogen with hydrogen to make ammonia has ΔH° = -92.2 kJ. What is the value of ΔE in kilojoules if the reaction is carried out at a constant pressure of 40.0 atm and the volume change is -1.12 L?
N_2(g) + 3 H_2(g) → 2 NH_3(g) ΔH° = -92.2 kJ
STRATEGY
We are given an enthalpy change ΔH, a volume change ΔV, and a pressure P and asked to find an energy change ΔE. Rearrange the equation ΔH = ΔE + PΔV to the form ΔE = ΔH – PΔV, and substitute the appropriate values for ΔH, P, and ΔV:
Note that ΔE is smaller (less negative) than ΔH for this reaction because the volume change is negative. The products have less volume than the reactants, so a contraction occurs and a small amount of PV work is gained by the system.