Question 8.SP.6: Calculating pH Using the [OH^-] What is the pH of an ammonia......
Calculating pH Using the [OH^{-}]
What is the pH of an ammonia solution with [OH^{-}]=3.7 ×10^{-3} M?
Step-by-Step
Step 1 Enter the [H_{3}O^{+}]. Because [OH^{-}] is given for the ammonia solution, we have to calculate [H_{3}O^{+}] using the K_{w} .When we divide through by the [OH^{-}] ,we obtain the [H_{3}O^{+}].
\frac{K_{w}}{[OH^{-}]}=\frac{[H_{3}O^{+}] \cancel{[OH^{-}]}}{\cancel{[OH^{-}]}}[H_{3}O^{+}]=\frac{1.0 ×10^{-14 } }{[3.7 ×10^{-3} ]}=2.7 ×10^{-12} M
pH= -log[2.7×10^{-12}]=2.7 \boxed{EE or EXP} 12 \boxed{+/-} \overset{Calculator Display}{2.7^{-12} or 2.7 E-12 }
Step 2 Press the log key and change the sign.
\boxed{log} \boxed{+/-} 11.56863
Step 3 Adjust the number of SFs on the right of the decimal point to equal the SFs in the coefficient.
\begin{matrix} 2.7 &\times 10^{-12}&M &&PH=11.57\\Two SFs& \longrightarrow &&&Two SFs on the right of the decimal point \end{matrix}
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