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Question 6.15: Calculating the Number of Moles of Solute in a Solution Hydr......

Calculating the Number of Moles of Solute in a Solution
Hydrochloric acid is sold commercially as a 12.0 M aqueous solution. How many moles of HCl are in 300.0 mL of 12.0 M solution?
STRATEGY
The number of moles of solute is calculated by multiplying the molarity of the solution by its volume in liters.

Step-by-Step
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\text{Moles of HCL} = (\text{Molarity of solution}) \times (\text{Volume of solution}) \\ = \frac{12.0 \ mol \ HCL}{1 \ \cancel{L}} \times 0.3000 \ \cancel{L} = 3.60 \ mol \ HCL
There are 3.60 mol of HCl in 300.0 mL of 12.0 M solution.
BALLPARK CHECK
One liter of 12.0 M HCl solution contains 12 mol of HCl, so 300 mL (0.3 L) of solution contains 0.3 \times 12 = 3.6 \ mol.

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