Can we conclude from the Hooke’s law data that the unloaded length of the spring is more than 4.9 in.?
This requires a hypothesis test. The null and alternate hypotheses are
H_{0} : \beta_{0} ≤ 4.9 versus H_{1} : \beta_{0} > 4.9
The quantity
\frac{\hat{\beta}_{0}\ −\ \beta_{0}}{s_{\hat{\beta}_{0}}}
has a Student’s t distribution with n − 2 = 20 − 2 = 18 degrees of freedom. Under H_{0}, we take \beta_{0} = 4.9. The test statistic is therefore
\frac{\hat{\beta}_{0}\ −\ 4.9}{s_{\hat{\beta}_{0}}}
We have previously computed \hat{\beta}_{0} = 4.9997 and s_{\hat{\beta }{_{0}}} = 0.0248. The value of the test statistic is therefore
\frac{4.9997\ −\ 4.9}{0.0248} = 4.020
Consulting the Student’s t table, we find that the P-value is less than 0.0005. (Software yields P = 0.0004.) We can conclude that the unloaded length of the spring is more than 4.9 in.